## How many 6 digit even numbers are there?

when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways. so total of 720 even numbers are possible.

## What is the chance of choosing the correct answer?

25%

## How many five digit number are there if the two leftmost digit are even the other digit are odd and the digit 4 Cannot appear more than once in the number?

The best answer is C. Now we deduct the possibilities where 4 does appear more than once (in this case it can appear only twice on the two leftmost even digits). In order to do so, we put 4 in the first and second leftmost digits. The rest of the digits are odd: 5*5*5=125.

## Is O even or odd?

Zero is an even number. In other words, its parity—the quality of an integer being even or odd—is even. This can be easily verified based on the definition of “even”: it is an integer multiple of 2, specifically 0 × 2.

## How many ways to answer 10 multiple choice questions when each question has 4 holes to tick assume that only 0 or 1 hole may be ticked?

510

## How many 5 digit odd numbers are possible if the leftmost digit Cannot be zero?

45,000

## What is the least 5-digit number divisible by 3?

10002

## How many 4-digit positive integers are there for which there are no repeated digits or for which there may be repeated digits but all digits are odd?

There are 9⋅9⋅8⋅7 4-digit integers that don’t contain any repeated digits.

## How many ways can you answer a 20 item multiple choice test with choices A B C D?

How many ways are there to fill out a 20 question Multiple Choice Exam? Since there are 5 ways to answer each question, there are 520 = 95, 367, 431, 640, 625 (95 trillion) possible answer keys.

## How many 4-digit numbers contain at least one 8 or 9?

Therefore, we have 8 choices (1 to 9, except 3) for the first digit, and 9 choices (0 to 9, except 3) for each of the other 3 digits. Therefore, 8 * 9 * 9 * 9 = 5832 4-digit numbers are possible without a digit 3. Therefore, number of 4-digit numbers containing at least one digit 3: = 9000 – 5832 = 3168.

## How many ways can a student answer the questions on the test if the student answers every question?

a) In how many ways can a student answer the questions on the test if the student answers every question? Here, there are 4 choices per question, and 10 questions. Choosing an answer for each question is a sequential task, so there are 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4=410 ways to answer.

## How many even 6 digit numbers are there?

720

## How many five digit natural numbers are there which remain five digit number when they are divided and multiplied by 3?

In the second option, however, since 0 can’t be the first digit, there are only 4 x 4 x 3 x 2 x 1 = 96 ways to form a five-digit number that is divisible by 3. Therefore, we have a total of 120 + 96 = 216 ways to form a five-digit number that is divisible by 3.

## How many 4 digits number are there with no digit repeated?

Thus, by multiplication principle, the required number of 4-digit numbers is 9×504=4536.

## How many 6 digit numbers are even or are divisible by 5?

Yes, we counted all the 6-digit numbers divisible by 5. There are 180000 six digit numbers divisible by 5. Out of the 180000 6-digit numbers divisible by 5, 90000 are even numbers and 90000 are odd numbers.

## How many even 4 digit whole numbers are there?

The fourth digit must be even, and there are 5 even digits (0, 2, 4, 6, or 8). Thus, the number of 4-digit even numbers is 9 x 10 x 10 x 5 = 4500.

## How many 4 digit odd numbers are possible if the leftmost digit Cannot be zero?

9

## How many 5 digit numbers are there if the two leftmost digits are even?

Most Helpful Expert Reply C. How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number. So, the answer is . Answer: C.

## What is the probability of guessing all of the correct answers?

Since all the answers are independent (the answer to one question has no bearing on the answers to the others), then this is the case with each question, so the chances of guessing all answers correctly is 1/3 × 1/3 × 1/3 = 1/27.

## How many 4 digit numbers are possible criteria being that all the four digits are odd?

How many four digit numbers are possible, criteria being that all the four digits are odd? 125.

## How many positive 4 digit numbers are there?

The first 999 numbers are only three or fewer digits long; 9999 is the last four digit number. Hence 9000 is the number of up-to-4 digit numbers minus the three-or-fewer digit numbers.

## How many 6 digit even numbers are possible if the leftmost digit Cannot be zero?

450000 six

## How many 4 digit numbers can be formed?

So, the required number of ways in which four digit numbers can be formed from the given digits is 9×9×8×7=4536.

## How many ways can a student do a 10 question True False exam if he or she can choose to not answer any number of questions?

There are 22 ways in which both questions may be answered true/false.

## How many ways can a student select five questions?

= 151200. If, on the other hand, one must answer question number 1, then, for the remaining 5 questions to be answered, you have (10–1)!/(10–1–5)! = 9!/4! = 9×8×7×6×5 = 15120 ways to answer 6 questions total.